Step 1: BOM (bill of Materials) For this Instructable you will need: 1 - LM7805 voltage regulator. 1 - Capacitor with the value of 0.33uF. 1 - Capacitor with the value of 0.1uF. 1 - 9 volt battery. 1 - 2.2 volt Red LED (you can use a different colored LED if you'd like, but then your final results may differ from what is displayed in the photos
It acts like potentiometer and output's voltage varies between 0 (0 bar pressure) and 5 volts (2.5 bar pressure). I would like to make the simplest possible circuit to limit the output voltage from the sensor to 4.5 volts, instead of 5v: INPUT - OUTPUT. 0.5v - 0.5v. 3v - 3v. 4.5v - 4.5v. 5v - 4.5v. Jan 28, 2016 at 1:36 3 Just FYI, the symbol in 19V⎓3.42A (two horizontal lines, top line solid, bottom line broken) is Unicode U+2393 ⎓ "direct current symbol form two". It means 19 volts DC. If the supply was labeled 19V~3.42A that would mean 19Vrms AC instead of 19V DC. – MarkU
0.1 V Moonlit night 1 lux 70 KΩ 80 KΩ0.07 mA 0.6 V Dark room 10 lux 10 KΩ 20 KΩ 0.25 mA 2.5 V Dark overcast day / Bright room 100 lux 1.5 KΩ 11.5 KΩ 0.43 mA 4.3 V Overcast day 1000 lux 300 Ω 10.03 KΩ 0.5 mA 5V This table indicates the approximate analog voltage based on the sensor light/ resistance w/a 5V supply and 10KΩ pulldown resistor.
It is compact, temperature, voltage and current stabilised and give a good reference voltage regardless of input (within limits) provides 1A and is cheap as chips (cheaper in fact). I use the all the time and managed to get 50 (in a tape) for £1.22! They also do different form factors and output voltages (i also use the 5V version).
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33,594. Jan 16, 2019. #2. The AAs or AAA's have more Ah capacity than a 9V, so will last longer. The 9V also wastes more energy when dropped to 5V. Note that if you run on four alkalines, which give 6V, you will need a very low dropout regulator for 5V output. C. Thread Starter. ezkl7r. 1033093158223134342023034
